Respuesta :
The magnetic force experienced by a proton moving with a speed of 3 ×[tex]10^{5}[/tex] m/s in the magnetic field B of magnitude 6 ×[tex]10^{-5}[/tex] T will be 2.88×[tex]10^{-18}[/tex] N.
Magnetic force can be defined as the attraction or repulsion force that arises between electrically charged particles due to the motion of the charged particles.
Given,
Speed = 3×[tex]10^{5}[/tex] m/s
Magnetic Field, B= 6 ×[tex]10^{-5}[/tex] T
Magnetic force is the product of velocity, the charge of a proton, and the magnetic field present there.
The magnetic force can be represented as:
F=qvB
F=1.6×[tex]10^{-19}[/tex]×3×[tex]10^{5}[/tex] ×6 ×[tex]10^{-5}[/tex]
F=2.88×[tex]10^{-18}[/tex] N
Hence, the magnetic force experienced by the proton will be 2.88×[tex]10^{-18}[/tex] N.
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