The volume is 2.608L
Given the value of n is 0.825 mole , pressure is 600mm = 0.789bar and Temperature = 300K
We need to calculate the volume in L
As we know the values of number of moles , pressure and Temperature is given
So , to calculate the volume we will use the ideal gas law
The equation of state for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has several restrictions, it is a decent approximation of the behavior of numerous gases under various circumstances.
Ideal gas law formula
PV = nRT
0.789*V = 0.825*8.3143*300
V = 0.825*8.314*300/0.789
V = 2.608*10^3
V = 2.608 L
Hence the Volume is 2.608 L
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