The equation of the graph is y ² = 16x.
A parabola is a U shaped curve ,all the point of which is equidistant from a point called as focus and a line called as Directrix .
In the given question , the graph is a horizontal parabola as the directrix is x = -4 , and as the focus lies on the right side , it is opening towards the right.
The equation for the horizontal parabola is given b y
(y-k)² = 4p(x-h)
h , k is the mid point of focus and the directrix , i.e. the vertex and is given by
h = ([tex]\rm x_f[/tex] +a )/2 , k = [tex]\rm y_f[/tex]
h = (4 -4)/2 , k = 0
h=0 , k = 0
The vertex is 0 , 0
p = (|[tex]\rm x_f[/tex] - a|)/2 = 8/2 = 4
Therefore the equation of the graph is
y ² = 4 * 4 *x
y ² = 16x
The equation of the graph is y ² = 16x.
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