contestada

Prove: m/EIF = m/GIH
Step
m/EIF+m/FIG = 180
m/FIG+m/GIH
= 180
m/EIF+mZFIG= m/FIG+mZGIH
m/EIF = m/GIH
Reason
Distributive Property Transitive Property of Equality Definition of Supplementary Angles
Subtraction Property of Equality Multiplication Property of Equality Simplify
Division Property of Equality Reflexive Property of Equality Addition Property of Equality
Substitution Property of Equality Definition of Complementary Angles
An
13
Se
Tea
16
Finis

Prove mEIF mGIH Step mEIFmFIG 180 mFIGmGIH 180 mEIFmZFIG mFIGmZGIH mEIF mGIH Reason Distributive Property Transitive Property of Equality Definition of Suppleme class=

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The question is incomplete. Below you will find the missing content in the figure.

Prove: m/EIF = m/GIH

Step                                                                    Reason

m∠EIF+m∠FIG = 180°

m∠FIG+m∠GIH= 180°

m∠EIF+m∠FIG= m∠FIG+m∠GIH

m∠EIF = m∠GIH

The figure is shown below.

The correct answer is m∠EIF = m∠GIH

Here lines FH and GE intersect each other at the point I.

we have to prove the angle

m∠EIF = m∠GIH

so,

m∠EIF+m∠FIG = 180° as angels ∠EIF and ∠FIG forming a linear pair summing up to 180°. angels ∠EIF and ∠FIG form straight angels on a line EG.

m∠FIG+m∠GIH= 180° as angels ∠FIG and ∠GIH forming a linear pair summing up to 180°. angels ∠FIG and ∠GIH form straight angels on a line FH.

m∠EIF+m∠FIG= m∠FIG+m∠GIH because of the substitution property of equality. we replace 180° by m∠FIG+m∠GIH.

m∠EIF = m∠GIH because of the subtraction property of equality. We can subtract the same elements from both sides by the subtraction property of equality.

Therefore m∠EIF = m∠GIH.

Learn more about property of equality

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