A rectangular parallelepiped has dimensions a, b and c. The volume is 100cm3. A second parallelepiped has dimensions α, β, γ, where α is 50% of a, β is 20% of b and γ is 10% of c. What is the volume of the second parallelepiped in cubic meters?

Respuesta :

The volume of the second parallelepiped will be 1 cm³. According to the given conditions, α is 50% of a, β is 20% of b and γ is 10% of c.

What is volume?

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

Given condition;

α is 50% of a, β is 20% of b and γ is 10% of c

α =  a/2

β = b/5

γ = c/10

The volume of the first parallelepiped:

V = abc

100cm³=abc

The volume of the second parallelepiped:

[tex]\rm V'= \alpha \times \beta \times \gamma \\\\ \rm V'= \frac{a}{2} \times \frac{b}{5} \times \frac{c}{10} \\\\ V' = \frac{abc}{100} \\\\ V'=\frac{100}{100} \\\\ V' = 1 cm^3[/tex]

Hence, the volume of the second parallelepiped willl be 1 cubic meter.

To learn more about the volume, refer to https://brainly.com/question/1578538

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