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The velocity of the water jet discharging from the orifice can be obtained from v=\12ih, where h = 2 m is the depth of the orifice from the water surface. Determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits from surface.


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Respuesta :

onyebuchinnaji

(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.

(b) The horizontal distance x where it hits from surface is 3.94 m.

Time for the water to reach the surface

The time of the water to reach the surface is calculated as follows;

h = ¹/₂gt²

2h = gt²

t² = 2h/g

t = √(2h/g)

where;

  • t is time of motion
  • h is height of the orifice

t = √( (2 x 2)/(9.8) )

t = 0.63 s

Horizontal distance

The horizontal distance is calculated as follows;

X = vt

where;

  • v is the velocity of the water = √2gh

X = (√2gh)t

X = (√2 x 9.8 x 2) x 0.63

X = 3.94 m

Learn more about horizontal distance here: https://brainly.com/question/24784992

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