A. The magnitude is 9.47N
B. The direction of the resultant force is 90°
We use vectors in answering this question.
F₁ = 2N 45°
F₂ = 5N 90°
F₃ = 4N. 135°
For the magnitude, we use vector addition twice
Consider forces F₁ and F₃
- Notice that F₁ and F₃ are at right angles to each other
- Using vector summation, the net forces of F₁ and F₃ say F₀ is the square root of the summation of the squares of F₁ and F₃
F₀ = 4.47N
Since F₁ and F₃ are at 45° and 135° respectively, their net force F₀ is at 90°, along the line of F₂
Fnet = F₀ + F₂ = 4.47 + 5 = 9.47N
A. The magnitude is 9.47N
B. The direction of the resultant force is 90°
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