In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then do the calculation.
How many ways are there to distribute 8 different books among 21 children if no child gets more than one book?
a.) Combination; Subscript 13 Baseline C Subscript 8 Baseline = 1287
b.) Combination; Subscript 21 Baseline C Subscript 8 Baseline = 203,490
c.) Permutation; Subscript 21 Baseline P Subscript 8 Baseline = 8,204,716,800
d.) Permutation; Subscript 13 Baseline P Subscript 8 Baseline = 51,891,840

Respuesta :

Using the permutation formula, it is found that the number of ways to distribute the books is given by:

c. 8,204,716,800

The order is important, as the books are different, hence the permutation formula is used to solve this question.

What is the permutation formula?

The number of possible permutations of x elements from a set of n elements is given by:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

In this problem, 8 books are distributed among 21 children, hence the number of ways is given by:

[tex]P_{21,8} = \frac{21!}{13!} = 8,204,716,800[/tex]

Which means that option c is correct.

More can be learned about the permutation formula at https://brainly.com/question/25925367

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