Zeros of Rational Functions
To find the zeros of a rational function, we must identify values of x that make the numerator equal to 0. We can do this by factoring and by keeping in mind the zero-product property.
The zero-product property states that if the product of two terms is 0, then one of the terms must be equal to 0.
Solving the Question
We're given:
[tex]f(x)=\dfrac{4x^2-36x}{x-9}[/tex]
First, factor 4x out of the numerator:
[tex]f(x)=\dfrac{4x(x-9)}{x-9}[/tex]
Let f(x) = 0:
[tex]0=\dfrac{4x(x-9)}{x-9}[/tex]
In this case, either x or (x-9) is equal to zero, as they are the two terms being multiplied in the numerator to get 0 as a product.
This makes the x-intercepts of this function 0 and 9.
However, the denominator in this function is x - 9. If x = 9, then it would make the denominator 0, which is not allowed. Therefore, x cannot equal 9, and the only x-intercept is 0.
Answer
x = 0
