5, the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)

Respuesta :

The average velocity is 4i m/sec

The average acceleration is 4i

What is a average velocity ?

Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. T

According to the question,

x=at²i + btj ( t is in second and x is in meter).

Average velocity =  [tex]\frac{dx}{dt}[/tex]

[tex]\frac{dx}{dt} = 2at i + b j\\\\\frac{dx}{dt} = 2 * 2 * t i +1 j\\\\\frac{dx}{dt} = 4t i +j[/tex]

[tex]\frac{dx}{dt}[/tex] in the time interval of 2 to 3 sec is

at 2 sec,

[tex]\frac{dx}{dt} = 4 * 2 i +j = 8i +j[/tex]

at 3 sec ,

[tex]\frac{dx}{dt}[/tex] = 4 * 3 i + j = 12i+j

Therefore the average velocity is

[tex]\frac{(12i +j - 8i -j)}{(3-2)} = 4i[/tex]

The velocity at any given time is   [tex]\frac{dx}{dt} = 4t i +j[/tex]

The acceleration at any given time is [tex]\frac{dx^2}{dt^2}[/tex]

[tex]\frac{dx^2}{dt^2} = 4 i[/tex]

The average acceleration in the time interval  t₁=2sec and t₂=3sec

Average Acceleration =  4i

Learn more about  average velocity here:

https://brainly.in/question/11504533

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