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help pleaaase!!
A train leaves the station from rest and travels along a straight track. if the train is 500 meters from the station when it reaches a velocity of 50m/s what is the acceleration of the train?

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Answer:

[tex]2.5m/s^{2}[/tex]

Explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]

Answer:

S=D÷T

Explanation:

50=0.5÷T

T= 100

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