A chain of length L has a mass of m which is uniformly distributed. When it is placed on a smooth horizontal table, 1/4 of its length hangs over the edge of the table (as shown in the figure). Then the chain slides away from the table freely, how much gravitational potential energy has changed from the beginning to the chain just sliding away from the table? (The height of the table from the ground is much greater than L)

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poojatomarb76 poojatomarb76 · Answer 1 · 2022-06-28T06:48:45+02:00

Gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

Length of hanging part, L/4

The gravitational potential energy is;

Work = Gravitational potential energy

Work done =force×displacement

[tex]\rm W = \frac{Mg}{3} \times \frac{L}{8} \\\\ W = \frac{MgL}{24}[/tex]

Hence, gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

To learn more about the gravitational potential energy, refer;

https://brainly.com/question/3884855

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