a. The voltmeter reads 0.053 volts
b. The electromotive force, emf of the battery is 0. 106 volts
How to determine the voltmeter reading
a. Given the current = 1. 15A
Voltmeter reads the voltage = V
Resistance could be gotten from the diagram = R
V = IR
To find the resistance from the structure
First, find the resistance in parallel
Resistance in parallel = 1/R1 = 1/R2 + 1/R3 = 1/25 + 1/15 + 1/15 = 0. 17 Ohms
Now, find the resistance in series
Resistance in series = R1 + R2 + R3 = 45 + 0. 17 + 10 = 55. 17 Ohms
Finally, the resistance in parallel = 1/35 + 1/55. 17 = 0. 028 + 0. 018 = 0. 046 Ohms
Substitute values into the equation
V = IR
V = 1. 15 * 0. 046
V = 0. 053 Volts
b. To find the Emf, use the formula
Emf = V + Ir
Substitute the values into the formula
Emf = 0. 053 + 1.15 * 0.046
Emf = 0. 053 + 0. 0529
Emf = 0. 106 volts
Therefore, the voltmeter reads 0.053 volts and the electromotive force of the battery us 0. 106 volts
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