Answer:
450 ML
Explanation:
Given:
Volume of gas sample: 550 mL Pressure: 1.8 atm plus 2.2 atm
To find:
The new volume of the gas after the pressure increases to 2.2 atm.
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steps
⇒ [tex]V_1P_1=V_2P_2[/tex]
⇒ [tex](550\text{ml})(1.8\text{atm})[/tex]
⇒ [tex]=(x)(2.2\text{atm})[/tex]
⇒ [tex]x=\frac{(550)(1.8)}{2.2}[/tex]
⇒ [tex]x=450\text{ml}[/tex]
Answer:
V₂ = 450 mL
Explanation:
Because you are dealing solely with pressure and volume, you can use Boyle's Law to find the missing value. The equation looks like this:
P₁V₁ = P₂V₂
In this formula, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You have been given values for all of the variables except for "V₂". Thus, you can substitute the given values into the equation and simplify to find the answer. The final answer should have 2 sig figs to match the given values.
P₁ = 1.8 atm V₁ = 550 mL
P₂ = 2.2 atm V₂ = ?
P₁V₁ = P₂V₂ <----- Boyle's Law equation
(1.8 atm)(550 mL) = (2.2 atm)V₂ <----- Plug given values in
990 = (2.2 atm)V₂ <----- Multiply 1.8 and 550
450 = V₂ <----- Divide both sides by 2.2
