Answer:
x = 5 , x = 6
Step-by-step explanation:
[tex]\sqrt{x-5}[/tex] = x - 5 ( square both sides )
x - 5 = (x - 5)² ← expand using FOIL
x - 5 = x² - 10x + 25 ← subtract x - 5 from both sides
0 = x² - 11x + 30 ← in standard form
0 = (x - 5)(x - 6) ← in factored form
equate each factor to zero and solve for x
x - 5 = 0 ⇒ x = 5
x - 6 = 0 ⇒ x = 6
As a check
substitute these values into the equation and if both sides are equal then these values are the solutions.
x = 5
left side = [tex]\sqrt{5-5}[/tex] = [tex]\sqrt{0}[/tex] = 0
right side = 5 - 5 = 0
then x = 5 is a solution
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x = 6
left side = [tex]\sqrt{6-5}[/tex] = [tex]\sqrt{1}[/tex] = 1
right side = 6 - 5 = 1
then x = 6 is a solution
