Answer:
[tex]\implies y=(x-2)^2-6[/tex]
Step-by-step explanation:
Vertex form of a quadratic equation:
[tex]y=a(x-h)^2+k[/tex]
where:
Given vertex: (2, -6)
⇒ h = 2 and k = -6
Substitute the values of h and k into the formula:
[tex]\implies y=a(x-2)^2+(-6)[/tex]
[tex]\implies y=a(x-2)^2-6[/tex]
As we have not been given a value for the constant [tex]a[/tex], assume this is 1.
Therefore, the vertex form of the quadratic function with vertex (2, -6) is:
[tex]y=(x-2)^2-6[/tex]
Learn more about vertex form here:
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