The remaining amount of the sample after 't' days would be 51. 74g
We have the formula for amount to be;
A = Ao × (1/2)^ t/t^1/2
Where
t1/2 = half -life = 138 days
t = 1
Ao = 52g
A = Amount after decay
Substitute into formula
A = 52 × (1/2) ^ 1/138
A = 52 ×
[tex] { \frac{1}{2} }^{0.00724} [/tex]
A = 52 × 0. 9950
A= 51. 74 g
Thus, the remaining amount of the sample after 't' days would be 51. 74g
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