The mass of NaHCO₃ required to produce 1.76 g of CO₂ is 3.36 g
Balanced equation
NaHCO₃ + HA --> NaA + CO₂ + H₂O
Molar mass of NaHCO₃ = 84 g/mol
Mass of NaHCO₃ from the balanced equation = 1 × 84 = 84 g
Molar mass of CO₂ = 44 g/mol
Mass of CO₂ from the balanced equation = 1 × 44 = 44 g
SUMMARY
From the balanced equation above,
44 g of CO₂ were produced from 84 g of NaHCO₃
How to determine the mass of NaHCO₃ needed
From the balanced equation above,
44 g of CO₂ were produced from 84 g of NaHCO₃
Therefore,
1.76 g of CO₂ will be produced from = (1.76 × 84) / 44 = 3.36 g of NaHCO₃
Thus, 3.36 g of NaHCO₃ is needed for the reaction
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