Respuesta :
Let the ages be a, b and c.
a+b+c = 47
Their ages 3 years ago were (a-3)+(b-3)+(c-3)
Thus 3 years ago, their ages were
a+b+c-9
But we know a+b+c = 47,
Thus their ages 3 years ago were
47 — 9
= 38
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a+b+c = 47
Their ages 3 years ago were (a-3)+(b-3)+(c-3)
Thus 3 years ago, their ages were
a+b+c-9
But we know a+b+c = 47,
Thus their ages 3 years ago were
47 — 9
= 38
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Was this worth your time?
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Answer:
38
Step-by-step explanation:
I'll say that Sana's age is A, Rabia's age is B, and Saleem's age is C.
A + B + C = 47
Three years ago, everyone was three years younger, so we can write the expression as:
(A-3) + (B-3) + (C-3) = x
x is the total age three years ago.
The above equation is the same thing as:
A + B + C - 9 = x
Since we know that A + B + C is 47, we use that number instead.
47 - 9 = x
38 = x
So three years ago, their total age was 38 years old.