ciarawaller04 ciarawaller04

21-07-2022
Mathematics

contestada

12.) tan L
A)
C)
√6
2
√6
w
L
√
V10
B)
D)
2
√6
√10
2
√10
M
N

12 tan L A C 6 2 6 w L V10 B D 2 6 10 2 10 M N class=

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Medunno13 Medunno13

21-07-2022

Answer: [tex]\frac{\sqrt{6}}{2}[/tex]

Step-by-step explanation:

By the Pythagorean theorem,

[tex]2^2 + (MN)^2 = (\sqrt{10})^2\\\\4+(MN)^2 = 10\\\\(MN)^2 = 6\\\\MN=\sqrt{6}\\\\\implies \tan L=\frac{\sqrt{6}}{2}[/tex]

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