50% of offspring have blue feathers.
Let's say the allele for blue feathers, which is dominant, is represented by "B" and that for white feathers, which is recessive, is represented by "b".
One parakeet has heterozygous alleles for blue feathers. Therefore its pair of genes will be represented as - Bb
Another parakeet is homozygous recessive for white feathers. Therefore its pair of genes will be represented as - bb
Gametes formed from Bb will be B and b
Gametes formed from bb will be b and b
Now the cross is made which is here shown by the Punnett square:
B b
b Bb bb
b Bb bb
Bb = blue feathers
bb = white feathers
The phenotypic ratio is = 1 : 1 (blue feathers : white feathers)
The genotypic ratio is = 1 : 1 (Bb : bb)
Therefore, 50% of the offspring have blue feathers and 50% have white feathers.
Learn more about Punnett square here:
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