The equation shows the relationship between a planet’s orbital period, t, and the planet’s mean distance from the sun, a, in astronomical units, au. If the orbital period of planet y is twice the orbital period of planet x, by what factor is the mean distance increased?.

Respuesta :

The mean distance is increased by a factor of [tex]2^{3/2}[/tex] if the orbital period  of planet y is twice that of the planet x.

Description of the Kepler's law.

The orbital period T and the mean distance from the sun, A, expressed in astronomical units (AU), are related in accordance with Kepler's third law.

The mathematical formula is,

T² = A³

Here, T denotes the orbital period and A represents the average separation or mean distance from the sun.

Now, if T(y) = 2T(x)

⇒ A'³(y) = 2A³(x)

A'(y) = [tex]2^{3/2}[/tex]A(y)

Thus, if orbital period of planet y is twice the orbital period of planet x, the mean distance is lengthened by a factor of [tex]2^{3/2}[/tex].

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