Answer:
The minimum cost of crashing the project that Roger Solano manages at Slippery Rock University by 4 days is $1100
Explanation:
The critical path of the project = Longest path of the project = CE
= 4 + 8
= 12 days
Other Paths = AD
= 6 + 5
= 11 days
In order to reduce project time by 4 days , we need to crash
C by 1 day,
E by 3 days
A by 1 day
D by 2 days
so as to have the total project duration be 8 days
Cost of crashing = Crashing cost of A, C, D, and E
= (1000 - 900) + (600 - 500) + (1200 - 900) + (1600-1000)
= 100 + 100 + 300 + 600
= $1100
