Respuesta :
The magnetic flux through the circular cross-sectional area of the solenoid is 0.00066 Weber or (Tm²).
What is a solenoid?
A wire tightly twisted in a lengthy, thin coil is a solenoid. Due to its design, the solenoid will have an electromagnet inside of it and a weak magnetic field surrounding it if we pass a current through it.
Equation of solenoid's magnetic field:
- The simplest solenoid to describe is one with unlimited length.
- An infinite solenoid's magnetic field has a constant within and a precise zero value outside.
- If we can accept that the magnetic field near the ends will be different from what is calculated for just an infinite solenoid, the unlimited solenoid is frequently a rough estimate of an actual, finite-length solenoid.
By utilizing the convolution operation as well as right hand rule, the magnetic field within a large solenoid is appropriately computed, but all of that can be condensed into:
B = (µ₀ × N × I )/ L
where
B = magnetic field (Tesla)
µ₀ = [tex]\pi[/tex]× 10^-7 (Tm/A ) is the vacuum permeability,
N = number of turns on solenoid,
I = electric current (Ampere)
L = length of the solenoid (m)
According to the question;
A diameter of solenoid 6.00 cm.
A radius of solenoid is 3 cm = 0.03m
Number of turns = 750
The length of solenoid is 10cm = 0.1m
Substitute all the values in equation to fine mangetic filed.
B = ([tex]\pi[/tex]×[tex]10^{-7}[/tex] × 750× 15 )/ 0.1
B = 0.035 Tesla
The formula for magnetic flux is
Ф = B×A
= B×([tex]\pi[/tex][tex]r^{2}[/tex])
= 0.035×[tex]\pi[/tex]×[tex].03^{2}[/tex]
Ф = 0.000099
Ф = 99×[tex]10^{-6}[/tex] Weber
Therefore, the magnetic flux through the circular cross-sectional area of the solenoid. is 99×[tex]10^{-6}[/tex] Weber.
To know more about the solenoid, here
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