An aircraft seam requires 21 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.) (a) If 23% of all seams need reworking, what is the probability that a rivet is defective

Probability of defect is perhaps the most important indicator of a manufacturing process's quality. It's a statistical technique used to indicate how often a product will fail during its lifespan, which in turn allows you to estimate the likelihood that an item will result in customer dissatisfaction.

Part A:

The number of rivets=22 rivets

Probability that no rivet is defective= [tex](1-p)^{22}[/tex]

The probability that at least one rivet is defective=1-[tex](1-p)^{22}[/tex]

For 19% of all seams need reworking, probability that a rivet is defective is given by

1-[tex](1-p)^{22}[/tex] = 0.19

[tex](1-p)^{22} = 1-0.19\\(1-p)^{22} = 0.81\\ p=1-\sqrt[22]{0.81} \\p=0.0095[/tex]

Part B:

For 9% of all seams need reworking, probability of a defective rivet is:

1-[tex](1-p)^{22}[/tex] = 0.09

[tex](1-p)^{22} = 1-0.09\\(1-p)^{22} = 0.91\\ p=1-\sqrt[22]{0.91} \\p=0.0043[/tex]

Hence, For Part A the probability is 0.0095 and for Part B the probability is 0.0043.

To learn more about the Probability from the given link:

https://brainly.com/question/14530744

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