The true mean expenditure per student is different from $10,337.
What is hypothesis in math?
Sample size is greater than 30 and the population standard deviation is given. Thus, in order to test
H0: µ =$10,337
H1: µ≠$10,337
The appropriate test is one sample z test.
The formula for one sample z test:
Z= x−μ / σ √ n
x−μ
x=10798
μ=10337
σ=1560
n=150
[tex]Z = \frac{10798 - 10337}{1560 / \sqrt{150} } = 3.62[/tex]
Computation of p-value:
The EXCEL formula to find the p-value for a two-tailed z-test is
“=2*(1-NORM.S.DIST(3.62, TRUE))”
Thus, the p-value obtained is 0.00029
Conclusion using α = 0.05:
Rejection rule using p-value:
If p-value ≤ α, then reject the null hypothesis.
Since, 0.00029 < 0.05, there is sufficient evidence to reject the null hypothesis.
Therefore, the true mean expenditure per student is different from $10,337.
Learn more about hypothesis
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