The average expenditure per student (based on average daily attendance) for a certain school year was $10,337 with a population standard deviation of $1560. A survey for the next school year of 150 randomly selected students resulted in a sample mean of $10, 798. Find the P-value

Respuesta :

The true mean expenditure per student is different from $10,337.

What is hypothesis in math?

  • A hypothesis is a proposition that is consistent with known data, but has been neither verified nor shown to be false.
  • There are basically two types, namely, null hypothesis and alternative hypothesis.

Sample size is greater than 30 and the population standard deviation is given. Thus, in order to test

H0: µ =$10,337

H1: µ≠$10,337

The appropriate test is one sample z test.

The formula for one sample z test:

Z=   x−μ / σ √ n

x−μ

​x=10798

μ=10337

σ=1560

n=150

[tex]Z = \frac{10798 - 10337}{1560 / \sqrt{150} } = 3.62[/tex]

Computation of p-value:

The EXCEL formula to find the p-value for a two-tailed z-test is

“=2*(1-NORM.S.DIST(3.62, TRUE))”

Thus, the p-value obtained is 0.00029

Conclusion using α = 0.05:

Rejection rule using p-value:

If p-value ≤ α, then reject the null hypothesis.

Since, 0.00029 < 0.05, there is sufficient evidence to reject the null hypothesis.

Therefore, the true mean expenditure per student is different from $10,337.

Learn more about hypothesis

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