The values of a and b which make the equation true are; a = 3 and b = 4 respectively.
From the question; the expression given is;
[tex]\sqrt{648} = \sqrt{2^{a} * 3^{b} }[/tex]
In essence; we have;
648 = 2^a × 3^b
By expression of of 648 as the product of its lowest factors; we have;
648 = 2 × 2 × 2 × 3 × 3 × 3 × 3.
In which case; we have;
648 = 2³ × 3⁴
Ultimately, the values of a and b which make the equation true are 3 and 4 respectively.
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The complete question is -
What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b Baseline EndRoot a = 3, b = 2 a = 2, b = 3 a = 3, b = 4 a = 4, b = 3