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A water sample has a pH 10 and contains 56 mg/L HCO3- and 32 mg/L CO32-. Calculate the alkalinity in mg/L as CaCO3.

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The alkalinity as CaCO3 in mg/L is 108,23

What is alkalinity?

Alkalinity is the total measure of substances present in water, capable of neutralizing acids. In other words, it is the amount of substances present in the water that act as a buffer.

With that being said;

Equivalent weight = {molar mass}*{ion charge/oxidation number}

  • Molar mass of HCO3- = 61g/mol
  • Molar mass of CO3 = 60g/mol
  • Molar mass of CaCO3 = 100g/mol

  • Eq. cot. of HCO3- = 61g/Eq
  • Eq. cot. of CO3 = 30g/Eq
  • Eq. cot. of CaCO3 = 50g/Eq

Alkalinity due to CO3 = {32x50}{30} = 53.33mg/L

Alkalinity due to HCO3- = {56x50}{61} = 54,90mg/L

Total Alkalinity = 53,33 + 54,90 = 108,23 mg/L

In this case, we have to The alkalinity as CaCO3 in mg/L is 108,23 mg/L

See more about pH at: brainly.com/question/15289741

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