Respuesta :
The points are (0,0) Minimum and (1/6, 1/18) is the saddle point.
What is the saddle point?
- A saddle point, also known as a minimax point, is a place on the surface of a function's graph where the slopes in orthogonal directions are all zero but the function does not have a local extremum.
To solve the question we have:
f(x,y) = xy(1-2x-6y)
Therefore, f(x,y) = xy-2x²y-6xy²
Finding the partial derivative of the above gives:
fₓ = y - 4xy-6y²
= x - 2x²-12xy
Therefore, when the above equations are set to 0 we get:
y - 4xy-6y² = 0.......(1)
x - 2x²-12xy = 0......(2)
Dividing equations (1) and (2) by y and x respectively give:
1 - 4x - 6y = 0
1 - 2x - 12y = 0
Solving gives:
x = 0.167 = 1/6
y = 0.056 = 1/18
When we place x in equation (1) we have:
y - 4(1/6)y-6y² = 0
y = 0 or y = 1/18
Similarly, x = 0 or 1/6
Therefore, the four critical points are:
(0,0) (1/6,1/18)
When x = 0 and y = 0
f(x,y) = 0 Hence this is a minimum
When x = 1/6 and y = 1/18
f (x,y) = 1/324 Which is a saddle point.
Therefore, the points are (0,0) Minimum, and (1/6, 1/18) is the saddle point.
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The question you are looking for is here:
(1 point) The function f(x,y)=xy(1−2x−6y) has 4 critical points. List them and select the type of critical point. Points should be entered as ordered pairs and listed in increasing lexicographic order. By that, we mean that (x,y) comes before (z,w) if x
