The correct steps to transform x^2 + 6x +8=0 into the form (x-p)² =q are;
x^2 + 6x +8 +1 = 0 + 1
x^2 + 6x +8 +1 = 1
x^2 + 6x + 9 = 1
(x+3)² = 1
Vertex form of a quadratic equation
The vertex form of a quadratic equation is expressed as:
a(x-h)² + k
Given the quadratic equation
x^2 + 6x +8=0
Subtract 8 from both sides
x^2 + 6x +8 - 8 = 0 - 8
x^2 + 6x = -8
Complete the square
(x^2+6x+3^2) = -8 + 9
(x+3)² = -8 + 9
(x+3)² = 1
Hence the correct steps to transform x^2 + 6x +8=0 into the form (x-p)² =q are;
x^2 + 6x +8 +1 = 0 + 1
x^2 + 6x +8 +1 = 1
x^2 + 6x + 9 = 1
(x+3)² = 1
learn more on completing the square here: https://brainly.com/question/13981588
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