The molality of the lithium ions is calculated as 0.906 m
What is the molality of lithium ions?
Given that the compound is written as Li₃PO₄, the dissociation of the compound is given by the equation;
Li₃PO₄ -----> 3Li^+ + PO₄^3-
Since there are three mole of lithium ions in the compound, it the follows that the molality of the lithium ions is;
3 * 0.302 m = 0.906 m
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