Respuesta :
The probabilities of each of the following are:
mu = 11, sigma = 2
We convert this to standard regular as
P( X < x) = P( Z < x - mu / sigma)
a)P( X >= 14) = P( Z >= 14 - 11 / 2)
= P( Z >= 1.5)
= 1 - P( Z < 1.5)
= 1 - 0.9332
=0.0668
b)P( X <= 85) = P (Z <= 8.5 - 11 / 2)
= P( Z <= -1.25)
= 1 - P( Z < 1.25)
= 1 - 0.8944
= 0.1056
c)P( 11.6 <= X <= 15.54) = P( X <= 15.54) - P( X <= 11.6)
= P( Z <= 15.54 - 11 / 2) - P( Z <= 11.6 - 11 / 2)
= P( Z <= 2.27) - P( Z <= 0.3)
= 0.9884 - 0.6179
= 0.3705
d)P( 6.4 <= X <= 14.4) = P( X <= 14.4) - P( X <= 6.4)
= P( Z <= 14.4 - 11 / 2) - P( Z <= 6.4 - 11 / 2)
= P( Z <= 1.7) - P( Z <= -2.3)
= 0.9554 - ( 1 - 0.9893)
= 0.9447
The opportunity of an event can be calculated with the aid of probability components by truly dividing the favorable number of consequences by using the entire wide variety of viable outcomes.
The probabilities are the branch of mathematics regarding numerical descriptions of how probably an event is to arise, or how possibly it's miles that a proposition is real. The chance of an event is a range of between 0 and 1, in which, roughly speaking, 0 indicates the impossibility of the occasion and 1 indicates certainty.
Three Types of Probability
- Classical: (equally probable outcomes) Let S=sample space (set of all possible distinct outcomes). ...
- Relative Frequency Definition. ...
- Subjective Probability.
Learn more about the probabilities here: https://brainly.com/question/24756209
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