The object can only stick out of the water because of the Archimede's principle.
Archimedes' principle states that the buoyant force acts vertically and upwards on bodies totally or partially immersed in fluids, moreover, according to this principle, such force has the same value as the weight of the fluid, displaced by the insertion of the body.
With that being said, following the Archimede's principle:
Weight of water displaced by floating object = Weight of object; so
Volume of water displaced = Part below water line; changing values and using the pseawater = [tex]1024kg/m^{3}[/tex]:
[tex]\frac{m}{\rho} \\\\\frac{1255}{1024} = 1,2255859375m^{3}[/tex]
Volume of entire object = [tex]\frac{m}{\rho}[/tex]
[tex]\frac{1255}{871} = 1,4408725603m^{3}[/tex]
Volume that sticks out of the water: Volume of entire object - Volume of water displaced; so: 1,4408725603 - 1,2255859375 = 0,2152866228m3
See more about buoyancy at: brainly.com/question/19168433
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