How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?

Respuesta :

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Reaction stoichiometry

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole
  • C₇H₆O₃: 1 mole
  • C₉H₈O₄: 1 mole
  • C₂H₄O₂: 1 mole

The molar mass of the compounds is:

  • C₄H₆O₃: 102 g/mole
  • C₇H₆O₃: 138 g/mole
  • C₉H₈O₄: 180 g/mole
  • C₂H₄O₂: 60 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole ×102 g/mole= 102 grams
  • C₇H₆O₃: 1 mole ×138 g/mole= 138 grams
  • C₉H₈O₄: 1 mole ×180 g/mole= 180 grams
  • C₂H₄O₂: 1  mole ×60 g/mole= 60 grams

Mass of aspirin formed

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

[tex]mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}[/tex]

mass of aspirin= 2.713 grams

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Learn more about the reaction stoichiometry:

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