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A $6$-sided die is weighted so that the probability of any number being rolled is proportional to the value of the roll. (So, for example, the probability of a $2$ being rolled is twice that of a $1$ being rolled.) What is the expected value of a roll of this weighted die

Respuesta :

The expected value of a roll of this weighted die is; 13/3 or 4.33

How to find the Expected Value?

We are given that;

A $6 sided die is weighted.

Probability of any number being rolled is proportional to the value of the roll.

Probability of a $2 being rolled is twice that of a $1 being rolled.

Thus, the expected Value is;

E(x) =  (1*1 + 2*2 + 3*3 + 4*4 + 5*5 + 6*6)/(1 + 2 + 3 + 4 + 5 + 6)

E(x) = 13/3 = 4.33

Read more about Expected Values at; https://brainly.com/question/24855677

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