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Determine the freezing point depression of a solution that contains 2 moles of NaCl in 200 g of water. ( Kf = 1.86°C/m and Kb = 0.512°C/m.)

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dsdrajlin

The freezing point depression of a solution that contains 2 moles of NaCl in 200 g of water (Kf = 1.86 °C/m) is 18.6 °C.

What is the freezing point depression?

It is a decrease in the freezing point of a solution, in comparison with the pure solvent.

  • Step 1. Determine the molality of the solution.

The solution contains 2 moles of NaCl in 200 g of water.

b = moles NaCl / Kg water = 2 mol/0.200 kg = 10 m

  • Step 2. Calculate the freezing point depression.

Given the cryoscopic constant (Kf) is 1.86 °C/m for water, the freezing point depression (ΔT) is:

ΔT = Kf × b = 1.86 °C/m × 10 m = 18.6 °C

The freezing point depression of a solution that contains 2 moles of NaCl in 200 g of water (Kf = 1.86 °C/m) is 18.6 °C.

Learn more about freezing point depression here: https://brainly.com/question/14115775

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