Answer:
Width = 5.5ft, Length = 8ft.
Step-by-step explanation:
Area of Rectangle = Length x Width
Let w be the Width of the rectangle.
From the information given from the question,
Length = 2w - 3 (3ft less than twice the width)
Area of Rectangle = [tex](2w-3)w\\=2w^{2} -3w[/tex] = 44
Now we can solve for w to find the dimensions.
[tex]2w^{2} -3w-44=0[/tex] (Quadratic Equations)
We can use the Quadratic formula to find w.
[tex]w=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}[/tex]
Since a = 2, b = -3 and c = -44,
[tex]w=\frac{-(-3)+/-\sqrt{(-3)^{2}-4(2)(-44) } }{2(2)} \\= 5.5 or -4 (reject)[/tex]
We reject negative values here.
Therefore, the width of the Rectangle = 5.5ft
While the length of the rectangle = 2(5.5) - 3 = 11 - 3 = 8ft
