Answer:
[tex]V_2 = \frac{5V}{8}[/tex]
Explanation:
I am assuming you are saying what is the final volume of the gas
Known :
Initial volume (V1) = V
Initial temperature (T1) = T
Final temperature (T2) = 5/4 T
Initial pressure (P1) = P
Final pressure (P2) = 2P
Wanted: Final volume (V2)
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{PV}{T} = \frac{(2P)V_2}{(5/4)T}\\\frac{V}{1} = \frac{(2)V_2}{5/4}\\5/4V = 2V_2\\\\V_2 = \frac{5V}{8}[/tex]
