By definite integrals and area formula of a rectangle, we find that the area of the region in the first quadrant is 147 / 4 square units.
Integrals can be used to determine the area of regions bounded by curves set on Cartesian plane. The upper limit of the integral of the question is initially found:
(2 / 3) · x = 7
x = 21 / 2
The area can be defined as an rectangle in the first quadrant minus the area below the linear equation:
[tex]A = \left(\frac{21}{2} \right) \cdot (7) - \frac{2}{3} \int\limits^{\frac{21}{2} }_{0} {x} \, dx[/tex]
[tex]A = \frac{147}{2} - \frac{1}{3} \cdot \left[\left(\frac{21}{2} \right)^{2}-0^{2}\right][/tex]
A = 147/4
By definite integrals and area formula of a rectangle, we find that the area of the region in the first quadrant is 147 / 4 square units.
The statement is poorly formatted and incomplete. Correct form is shown below:
A region in the first quadrant is bounded by the line y = (2/3) · x, the y-axis and the horizontal line y = 7. Determine the area of the region.
To learn more on definite integrals: https://brainly.com/question/14279102
#SPJ1
