contestada

What mass of Ni2+ is produced in solution by passing a current of 67.0 A period od 14.0 h, assuming the cell is 86.0 % efficient?

Respuesta :

883.15 gm of Ni is produced in solution by passing a current of 67 Ampere through a period of 14 hours.

Solution of the problem.

Current, I = 67 A

Time, t = 14 h = (14×60×60) s

Now total Charge passed , Q = I t = 67×14×60×60 = 3376800 C

moles of electrons passed = [tex]\frac{Q}{96500}[/tex][tex]=\frac{3376800}{96500}=34.992[/tex] mole  e⁻

34.992 moles of e⁻ will produce 34.992 /2 = 17.49 mole Ni

Now we have the reaction

Ni ²⁺ + 2e⁻ → Ni

34.992 moles of e⁻ produces 17.49 mole of Ni

mass of Ni produced = molar mass of Ni × moles of Ni = 58.693 × 17.49 = 1026.91 gm of Ni produced

But the cell is 86% efficient.

Therefore, Ni produced = 0.86×1026.91 =  883.15 gm

Learn more about Ni here :

https://brainly.com/question/4203706

#SPJ1