Assume that helium behaves as an ideal gas. what is the estimated density of 1.0 g of helium gas at a temperature of 27 °c and a pressure of 3.0 atm? (note: use r = 0.0821 l∙atm∙mol−1∙k−1)

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smecloudbird18 smecloudbird18 · Answer 1 · 2022-07-29T10:35:00+02:00

The density of the helium gas is 0.487 g/L

Calculation,

According to Ideal gas equation,

PV = nRT ...(I)

The values of some terms are given as,

P is the pressure = 3 atm

V is the volume = ?

T is the temperature = 27°C = 27°C + 273 = 300 K

R is the universal gas constant = 0.0821 L∙atm∙mol−1∙K−1

n is the number of moles of helium = given mass of helium/molar mass of helium

n is the number of moles of helium = 1 g/ 4 g/mole = 0.25 mole

So, by putting the value of all data given in the equation (i) we get,

3 atm × V = 0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K

V = 0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K/3 atm

V = 2.05 L

The formula of density = given mass /volume = 1g/2.05 L = 0.487 g/L

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