There are 17 hops in a hop, a skip, and a jump.
How to perform changes of units?
We have the relations:
- 1 skip = 4 hops.
- 1 jump = 3 skips.
How many hops are in a hop, a skip and a jump?
So we have:
1 hop + 1 skip + 1 jump.
First, using the second relation we rewrite:
1 hop + 1 skip + 3 skips = 1 hop + 4 skips.
Now, using the first relation:
1 hop + 4 skips = 1 hop + 4*(4 hops) = 1 hop + 16 hops = 17 hops.
There are 17 hops in a hop, a skip, and a jump.
If you want to learn more about changes of units:
https://brainly.com/question/9032119
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