The mean of the data given is 13.4364 and.the standard deviation is 1.788.
It should be noted that the mean is the average of the giving set of numbers. In this situation, the mean is 3.1998.
E(X²) will be:
= (0² × 0.0408) + (1² × 0.1304) .... + (12² × 0.0001)
= 13.4364
Var(X) = 13.4364 - 3.1998²
= 3.198
The standard deviation will be:
= ✓3.198
= 1.788
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