Respuesta :
The ratio of the geometric sequence 40[tex]2^{n-1}[/tex] is 2.
Given that geometric sequence is 40*[tex]2^{n-1}[/tex] and we have to find the common ratio of all the terms.
Geometric sequence is a sequence in which all the terms have a common ratio.
Nth termof a GP is a[tex]r^{n-1}[/tex] in which a is first term and r is common ratio.
Geometric sequence=40*[tex]2^{n-1}[/tex]
We have to first find the first term, second term and third term of a geometric progression.
First term=40*[tex]2^{1-1}[/tex]
=40*[tex]2^{0}[/tex]
=40*1
=40
Second term=40*[tex]2^{2-1}[/tex]
=40*[tex]2^{1}[/tex]
=40*2
=80
Third term=40*[tex]2^{3-1}[/tex]
=40*[tex]2^{2}[/tex]
=40*4
=160
Ratio of first two terms=80/40=2
Ratio of next two terms=160/80=2
Hence the common ratio of geometric sequence is 2.
Learn more about geometric progression at https://brainly.com/question/12006112
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