An 87-kg football player traveling 5.2 m/s is stopped in 1.0 s by a tackler.
What is the original kinetic energy of the player?
Express your answer to two significant figures and include the appropriate units.
What average power is required to stop him?
Express your answer to two significant figures and include the appropriate units.

Respuesta :

The original kinetic energy of the player and the average power is required to stop him are 1200 J and 1200 W respectively.

What is Kinetic Energy ?

The energy possessed by a body in motion is known as Kinetic Energy. The S. I unit is Joule.

Given that an 87-kg football player traveling 5.2 m/s is stopped in 1.0 s by a tackler. The given parameters are;

  • Mass m = 87 Kg
  • Velocity v = 5.2 m/s
  • Time t = 1 s

The original kinetic energy of the player can be calculated by using the formula K.E = 1/2m[tex]v^{2}[/tex]

Substitute all the parameters into the formula

K.E = 1/2 x 87 x [tex]5.2^{2}[/tex]

K.E = 1176.24

K.E = 1200 J

Power is the rate at which work is done.

Work done = energy

The average power is required to stop him can be calculated by using the formula P = E/t

Substitute all the parameters into the formula

P = 1200/1

P = 1200 W

Therefore, the original kinetic energy of the player and the average power is required to stop him are 1200 J and 1200 W respectively.

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