an ambulance with a siren emitting a whine at 1600Hz overtakes and passes a cyclist pedaling a bike at 2.44 m/s. After being passed the cyclist hears a frequency of 1590 Hz. How fast was ambulance moving

Respuesta :

The speed of the ambulance is 4.61 m/s.

Calculation:

Doppler's effect formula is used, which is

[tex]f' = f (\frac{v + vo}{v + vs})[/tex]

Where,

f' = observer frequency of sound

f = actual frequency of sound waves

v = speed of sound waves

vo = velocity of observer

vs = velocity of source

Here, observer is the cyclist and source is the ambulance.

Given,

f' = 1590 Hz

f = 1600 Hz

v = 343 m/s

vo = 2.44 m/s

Now put the given values in the above formula,

[tex]f' = f (\frac{v + vo}{v + vs})[/tex]

[tex]1590 = 1600 (\frac{343 + 2.44}{343 + vs})[/tex]

[tex]1590 = 1600( \frac{345.44}{343 + vs})[/tex]

[tex]1590 = \frac{552,704}{343+vs}[/tex]

[tex]343+vs = \frac{552,704}{1590\\}[/tex]

[tex]343 + vs = 347.61\\[/tex]

[tex]vs = 347.61 - 343[/tex]

[tex]vs = 4.61 m/s[/tex]

Hence, the speed of the ambulance is 4.61 m/s.

Learn more about doppler effect here:

https://brainly.com/question/1330077

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