There are two real roots for the quadratic equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
In this question we must apply algebraic handling to simplify a quadratic equation and find the roots that satisfy the expression. Completing the square consists in transforming part of the equation into a perfect square trinomial, and then we clear for x:
x² - 8 · x + 13 = 0
x² - 8 · x + 16 = 3
(x - 4)² = 3
x - 4 = ± √2
x = 4 ± √2
There are two real roots for the quadratic equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
To learn more on quadratic equations: https://brainly.com/question/2263981
#SPJ1