a.
- i. In standard form y = 5x² - 20x + 27
- ii. The y intercept is (0, 27)
- iii. Find the graph in the attachment
b.
- i. In standard form is y = 3x² + 6x + 15
- ii. The y-intercept is (0, 15)
- iii. Find the graph in the attachment
What is a quadratic function?
A quadratic function is a function of the form y = ax² + bx + c
a.
i. How to write the quadratic function y = 5(x - 2)² + 7 in standard form?
To write y = 5(x - 2)² + 7, we expand the bracket and simplify.
So, y = 5(x - 2)² + 7
y = 5(x² - 4x + 4) + 7
y = 5x² - 20x + 20 + 7
y = 5x² - 20x + 27
So, the quadratic function y = 5(x - 2)² + 7 in standard form is y = 5x² - 20x + 27
ii. The y-intercept
The y intercept is gotten when x = 0.
So, y = 5x² - 20x + 27
y(0) = 5(0)² - 20(0) + 27
y(0) = 0 - 0 + 27
y(0) = 27
The y intercept is (0, 27)
iii. The graph of y = 5(x - 2)² + 7
Find the graph in the attachment
b.
i. How to write the quadratic function y = 3(x + 1)² + 12 in standard form?
To write y = 3(x + 1)² + 12, we expand the bracket and simplify.
So, y = 3(x + 1)² + 12
y = 3(x² + 2x + 1) + 12
y = 3x² + 6x + 3 + 12
y = 3x² + 6x + 15
So, the quadratic function y = 3(x + 1)² + 12 in standard form is y = 3x² + 6x + 15
ii. The y-intercept
The y intercept is gotten when x = 0.
So, y = 3x² + 6x + 15
y(0) = 3(0)² - 6(0) + 15
y(0) = 0 - 0 + 15
y(0) = 15
The y-intercept is (0, 15)
iii. The graph of y = 3(x + 1)² + 12
Find the graph in the attachment
Learn more about quadratic function here:
https://brainly.com/question/25841119
#SPJ1
