Tension in the rope C is 1.24× 10² N.
To find the answer, we need to know about the horizontal component of tension in the rope B.
What's the angle made by the rope B by horizontal?
- From the figure of the answer, in the triangle PQR, tan(θ)= PQ/QR = 6/1= 6
- θ= tan inverse of 6 = 80.5°
What's the horizontal component of the tension in rope B?
Horizontal component= tension in rope B × cos80.5°
= 7.52×10² N × cos80.5°
= 1.24×10² N
What's the tension in the rope C?
- From the figure, we have found that the tension in rope C = horizontal component of the tension in rope B
- So, tension in rope C= 1.24×10² N
Thus, we can conclude that the tension in the rope C is 1.24× 10² N.
Learn more about the tensional force here:
brainly.com/question/2008782
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