Find CE if AE = 8 and BC = 3. Round to the nearest tenth. AE is tangent to the circle. (Hint: May need quadratic formula)

The value of CE = 18.3
According to the statement
Here we have given the value of tangents AE = 8 and BC = 3
we have to find the value of CE and
It is given that AE is the tangent to the circle.
Now we make a equation to find the CE then
(8)^2 = 3(x+3)
In this equation the value of AE is 8. and
In this x is the value of CE and BC have value 3.
And the total value of BE becomes the 3(x+3) and 3 is the parts by which BE is formed.
Then solve the equation
64= 3x +9
3x = 64-9
x = 18.3
So, The value of CE = 18.3
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